Java Datatypes || Hackerrank Solution

 Java Datatypes:

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we'll work with the primitives used to hold integer values (byte, short, int, and long):

  • byte is an 8-bit signed integer.
  • short is a 16-bit signed integer.
  • An int is a 32-bit signed integer.
  • long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Reference: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Input Format

The first line contains an integer, , denoting the number of test cases.
Each test case, , is comprised of a single line with an integer, , which can be arbitrarily large or small.

Output Format

For each input variable  and appropriate primitive , you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: ).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation

 can be stored in a short, an int, or a long.

 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.


  • Solution:

import java.util.*;

import java.io.*;

class Solution{

    public static void main(String []argh)

    {

        Scanner sc = new Scanner(System.in);

        int t=sc.nextInt();


        for(int i=0;i<t;i++)

        {


            try

            {

                long x=sc.nextLong();

                System.out.println(x+" can be fitted in:");

                if(x>=-128 && x<=127)System.out.println("* byte");

                if(x>=-32768 && x<=32767)System.out.println("* short");

                if(x>=-2147483648 && x<=2147483647)System.out.println("* int");

                if(x>=-(Math.pow(2,63)) && x<=Math.pow(2,63)-1){

                    System.out.println("* long");

                }

            }

            catch(Exception e)

            {

                System.out.println(sc.next()+" can't be fitted anywhere.");

            }

        }

    }

}


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Java Datatypes || Hackerrank Solution Java Datatypes || Hackerrank Solution Reviewed by CodexRitik on November 07, 2020 Rating: 5

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