Printing Pattern using Loops - Hackerrank solution

 

Printing Pattern Using Loops

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Task

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Print a pattern of numbers from 1 to n as shown below. Each of the numbers is separated by a single space.

4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4

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Solution:

#include <stdio.h> int main() {     int n, i, j, t;      scanf("%d", &n);     t = 2 * n - 1;     i = t;      j = t;     int a[i][j], k, m, p;     p = n;     m = 0;     for (k = 0; k < p; k++) {         for (i = m; i < t; i++) {             for (j = m; j < t; j++) {                 if (i == m || i == (t - 1) || j == m || j == (t - 1)) {                     a[i][j] = n;                     if (n == 1) {                         break;                     }                 }             }         }         t = t - 1;         n = n - 1;         m = m + 1;     }     t = 2 * m - 1;     for (i = 0; i < t; i++) {         for (j = 0; j < t; j++) {             printf("%d ", a[i][j]);         }         printf("\n");     }     return 0; }

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Note:

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