For Loop in C - Hackerrank solution

 

For Loop in C

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Objective

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In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.
The syntax for this is
for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>
expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
expression_3 is generally used to update the flags/variables.
A sample loop will be

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for(int i = 0; i < 10; i++) {
...
}

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Task

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For each integer n in the interval [a,b] (given as input) :
If 1<= n <=9, then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
Else if n>9 and it is an even number, then print "even".
Else if n>9 and it is an odd number, then print "odd".

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Solution:

#include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> int main()  {     int a, b;     scanf("%d\n%d", &a, &b);          char labels[11][6] = {"one", "two", "three", "four", "five",  "six", "seven", "eight", "nine", "even", "odd"};     int labels_index;       for (int i=a; i<=b; i++) {         labels_index = i <= 9 ? i - 1 : 9 + i % 2;         printf("%s\n", labels[labels_index]);     }     return 0; }

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Note:

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